| 일 | 월 | 화 | 수 | 목 | 금 | 토 |
|---|---|---|---|---|---|---|
| 1 | 2 | 3 | ||||
| 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| 11 | 12 | 13 | 14 | 15 | 16 | 17 |
| 18 | 19 | 20 | 21 | 22 | 23 | 24 |
| 25 | 26 | 27 | 28 | 29 | 30 | 31 |
- spa
- S/4 HANA
- r/2
- dense_rank()
- asc
- 공공데이터
- R/3
- 티스토리챌린지
- union
- order by
- SQL
- CSV
- left join
- json
- DateDiff
- join
- ERP
- group by
- SAP HANA
- 오블완
- %_%
- SERVICE_KEY_IS_NOT_REGISTERED_ERROR
- stratascratch
- 중복 컬럼
- desc
- Where
- limit
- over()
- between
- HAVING
- Today
- Total
목록between (2)
RE:cord
[SQL] Analyzing User Retention (유저 리텐션 분석) (DATEDIFF / BETWEEN AND / HAVING)
* 문제 애매한 점 정의 - reservation date가 따로 없음. ⇒ activity_date를 reservation date로 취급 - 가입일에만 접속 로그가 남아있는 사용자 처리 조건 명시 x -> 가입일에만 접속한 사람도 활동유저로 집계 SELECT ua.user_id, ua.activity_date, COUNT(ua.activity_date)FROM user_profiles AS up JOIN user_activities AS ua ON up.user_id = ua.user_idWHERE DATEDIFF(activity_date, signup_date) BETWEEN 0 AND 30GROUP BY up.user_id--HAVING COUNT(up.user_id)>0-- * ..
[SQL] UNION / COUNT / BETWEEN
SELECT games FROM olympics_athletes_events WHERE age = (SELECT max(age) FROM olympics_athletes_events) UNION SELECT games FROM olympics_athletes_events WHERE age = (SELECT min(age) FROM olympics_athletes_events); select count(order_id) from shopify_orders; SELECT worker_id, login_timestamp FROM worker_loginsWHERE login_timestamp BETWEEN '2021-12-13 00:00:00' AND '2021-12-19 23:59:59'; Just i..